Date: 2/20/2001, 8:38 pm
Wow.
Have you reached any conclusions yet about your own layup? Please keep us in the loop if you do.
: I have read Open Water Kayak’s “Standard Engineering Model” and have some
: questions. I have attempted to cross reference the concepts with E.P.
: Popov’s Mechanics of Materials..
: (Smax I)/
: ((Tw+Tg)/2)
: Popov calls this the “Flexure Formula”;
: ((Tw+Tg)3 - Tw3) + Tw3(Ew/Eg) /12
: Popov describes this formula for moment of inertia as “transformation of a
: section”.
: (M2 L )/
: (2 I Eg)
: This formula is the maximum amount of strain energy a cantilevered beam can
: store without failing.
: 98/12
: The density of glass is needed to determine the thickness of the glass
: portion of the composite.
: 22/12
: The density of wood is needed to determine the weight of the wood portion of
: the composite.
: (WPw W)/Dw
: The thickness of the wood is needed to calculate moment of inertia.
: ((1-WPw) W)/Dg
: The thickness of the glass is needed to calculate moment of inertia.
: 600*Tg
: Where is this used?
: .05 Eg = Ew
: This is used in the transformation method of computing the composite section
: moment of inertia.
: (((Tw+Tg)3 - Tw3) + Tw3(Ew/Eg)) Eg /12
: This is the moment of inetia times the modulus of glass, as described in
: Popov’s transformation of sections.
: 18W3Eg (1331+13794WPw+47652WPw2-(62777 +117649Ew/Eg)WPw3 ) /156590819
: I tried to expand the equations above and did not come up with this result.
: Can you show some intermediate steps?
: In the above equation, the static strength does appear to vary according to
: the square of the weight, when wood as a % of weight is constant.
: In the above equation, the static strength does appear to vary according to
: the tensile strength, when wood as a % of weight is constant.
: Then, fixing all variables except the wood as a % of weight you found a curve
: with a peak at .63%. I used the calculation for the moment of inetia times
: the modulus of glass, as above before the substitutions to calculate the
: curve as a check. Keeping W constant and keeping the wood as a percent of
: weight constant, the curve did not have a peak. Similarly, the static and
: dynamic curves did not peak. Should I have seen a peak using equations for
: before the substitutions were made?
: Your dimensional analysis approach is very intriguing, and would be very
: useful provided it is understood. I am ready to start fiberglassing, and
: this discussion has already given me a lot to consider.
: Thanks in advance for any help you can give. I like many others am very
: grateful for the level of commitment and effort that the builders on this
: site have for helping us novices.
: Tom
Messages In This Thread
- A step forward
Sam McFadden -- 2/19/2001, 9:11 pm- Method for optimizing kayak shell
Tom Tieman -- 2/25/2001, 3:00 pm- Re: Method for optimizing kayak shell
Sam McFadden -- 2/25/2001, 11:01 pm
- Questions
Tom Tieman -- 2/20/2001, 8:25 pm- Re: Questions
Pete Rudie -- 2/20/2001, 8:38 pm
- Re: Possible Reaction . . . *Pic*
Spidey -- 2/19/2001, 10:48 pm - Re: Method for optimizing kayak shell
- Method for optimizing kayak shell